Solve b_{1}190,000=0.1(1+1)^x

$$b _ { 1 } 190,000 = 0.1 ( 1 + 1 ) ^ { x }$$

Solve for b_1

$$b_{1}=\frac{2^{x}}{1900000}$$

Steps for Solving Linear Equation

Add 1 and 1 to get 2.

$$b_{1}\times 190000=0.1\times 2^{x}$$

The equation is in standard form.

$$190000b_{1}=\frac{2^{x}}{10}$$

Divide both sides by 190000.

$$\frac{190000b_{1}}{190000}=\frac{2^{x}}{10\times 190000}$$

Dividing by 190000 undoes the multiplication by 190000.

$$b_{1}=\frac{2^{x}}{10\times 190000}$$

Divide \frac{2^{x}}{10} by 190000.

$$b_{1}=\frac{2^{x}}{1900000}$$

Solve for x (complex solution)

$$x=\frac{\ln(b_{1})+\ln(1900000)}{\ln(2)}+\frac{i\times 2\pi n_{1}}{\ln(2)}$$

$$n_{1}\in \mathrm{Z}$$

$$b_{1}\neq 0$$

Solve for x

$$x=\frac{\ln(b_{1})+\ln(1900000)}{\ln(2)}$$

$$b_{1}>0$$