Solve b_{0}=(2-3)*(1-3^2)-[7-(-10):(5-10)]=

$$b _ { 0 } = ( 2 - 3 ) \cdot ( 1 - 3 ^ { 2 } ) - [ 7 - ( - 10 ) : ( 5 - 10 ) ] =$$

Solve for b_0

$$b_{0}=3$$

Steps for Solving Linear Equation

Subtract 3 from 2 to get -1.

$$b_{0}=-\left(1-3^{2}\right)-\left(7-\frac{-10}{5-10}\right)$$

Calculate 3 to the power of 2 and get 9.

$$b_{0}=-\left(1-9\right)-\left(7-\frac{-10}{5-10}\right)$$

Subtract 9 from 1 to get -8.

$$b_{0}=-\left(-8\right)-\left(7-\frac{-10}{5-10}\right)$$

Multiply -1 and -8 to get 8.

$$b_{0}=8-\left(7-\frac{-10}{5-10}\right)$$

Subtract 10 from 5 to get -5.

$$b_{0}=8-\left(7-\frac{-10}{-5}\right)$$

Divide -10 by -5 to get 2.

$$b_{0}=8-\left(7-2\right)$$

Subtract 2 from 7 to get 5.

$$b_{0}=8-5$$

Subtract 5 from 8 to get 3.

$$b_{0}=3$$

Assign b_0

$$b_{0}≔3$$