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b-3=\sqrt{8}
Calculate the square root of 9 and get 3.
b-3=2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
b=2\sqrt{2}+3
Add 3 to both sides.