Solve b(b-2)(b+1)-3-3b

$$b ( b - 2 ) ( b + 1 ) - 3 - 3 b$$

Evaluate

$$\left(b-3\right)\left(b+1\right)^{2}$$

Solution Steps

Use the distributive property to multiply b by b-2.

$$\left(b^{2}-2b\right)\left(b+1\right)-3-3b$$

Apply the distributive property by multiplying each term of b^{2}-2b by each term of b+1.

$$b^{3}+b^{2}-2b^{2}-2b-3-3b$$

Combine b^{2} and -2b^{2} to get -b^{2}.

$$b^{3}-b^{2}-2b-3-3b$$

Combine -2b and -3b to get -5b.

$$b^{3}-b^{2}-5b-3$$

Expand

$$b^{3}-b^{2}-5b-3$$

Solution Steps

Use the distributive property to multiply b by b-2.

$$\left(b^{2}-2b\right)\left(b+1\right)-3-3b$$

Apply the distributive property by multiplying each term of b^{2}-2b by each term of b+1.

$$b^{3}+b^{2}-2b^{2}-2b-3-3b$$

Combine b^{2} and -2b^{2} to get -b^{2}.

$$b^{3}-b^{2}-2b-3-3b$$

Combine -2b and -3b to get -5b.

$$b^{3}-b^{2}-5b-3$$