Solve b*x^3+8x^2+24x+27=0

$$b \cdot x ^ { 3 } + 8 x ^ { 2 } + 24 x + 27 = 0$$

Solve for b

$$b=-\frac{8x^{2}+24x+27}{x^{3}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 8x^{2} from both sides. Anything subtracted from zero gives its negation.

$$bx^{3}+24x+27=-8x^{2}$$

Subtract 24x from both sides.

$$bx^{3}+27=-8x^{2}-24x$$

Subtract 27 from both sides.

$$bx^{3}=-8x^{2}-24x-27$$

The equation is in standard form.

$$x^{3}b=-8x^{2}-24x-27$$

Divide both sides by x^{3}.

$$\frac{x^{3}b}{x^{3}}=\frac{-8x^{2}-24x-27}{x^{3}}$$

Dividing by x^{3} undoes the multiplication by x^{3}.

$$b=\frac{-8x^{2}-24x-27}{x^{3}}$$

Divide -8x^{2}-24x-27 by x^{3}.

$$b=-\frac{8x^{2}+24x+27}{x^{3}}$$