Solve for b (complex solution)
\left\{\begin{matrix}b=-\frac{c+7}{x}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&c=-7\text{ and }x=0\end{matrix}\right.
Solve for b
\left\{\begin{matrix}b=-\frac{c+7}{x}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&c=-7\text{ and }x=0\end{matrix}\right.
Solve for c
c=-\left(bx+7\right)
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bx=-7-c
Subtract c from both sides.
xb=-c-7
The equation is in standard form.
\frac{xb}{x}=\frac{-c-7}{x}
Divide both sides by x.
b=\frac{-c-7}{x}
Dividing by x undoes the multiplication by x.
b=-\frac{c+7}{x}
Divide -7-c by x.
bx=-7-c
Subtract c from both sides.
xb=-c-7
The equation is in standard form.
\frac{xb}{x}=\frac{-c-7}{x}
Divide both sides by x.
b=\frac{-c-7}{x}
Dividing by x undoes the multiplication by x.
b=-\frac{c+7}{x}
Divide -7-c by x.
c=-7-bx
Subtract bx from both sides.
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