Solve b^7a^4(-100ca^3)(-a^2bc)

$$b ^ { 7 } a ^ { 4 } ( - 100 c a ^ { 3 } ) ( - a ^ { 2 } b c )$$

Evaluate

$$100c^{2}b^{8}a^{9}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 7 and 1 to get 8.

$$b^{8}a^{4}\left(-100\right)ca^{3}\left(-a^{2}\right)c$$

To multiply powers of the same base, add their exponents. Add 4 and 3 to get 7.

$$b^{8}a^{7}\left(-100\right)c\left(-a^{2}\right)c$$

Multiply c and c to get c^{2}.

$$b^{8}a^{7}\left(-100\right)c^{2}\left(-a^{2}\right)$$

Multiply -100 and -1 to get 100.

$$b^{8}a^{7}\times 100c^{2}a^{2}$$

To multiply powers of the same base, add their exponents. Add 7 and 2 to get 9.

$$b^{8}a^{9}\times 100c^{2}$$

Differentiate w.r.t. b

$$800c^{2}b^{7}a^{9}$$