Solve b^6-9(c-2)^2

$$b ^ { 6 } - 9 ( c - 2 ) ^ { 2 }$$

Evaluate

$$b^{6}-\left(3c-6\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(c-2\right)^{2}.

$$b^{6}-9\left(c^{2}-4c+4\right)$$

Use the distributive property to multiply -9 by c^{2}-4c+4.

$$b^{6}-9c^{2}+36c-36$$

Expand

$$b^{6}-9c^{2}+36c-36$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(c-2\right)^{2}.

$$b^{6}-9\left(c^{2}-4c+4\right)$$

Use the distributive property to multiply -9 by c^{2}-4c+4.

$$b^{6}-9c^{2}+36c-36$$