Factor
\left(b-2c\right)\left(b^{2}+2bc+4c^{2}\right)
Evaluate
b^{3}-8c^{3}
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\left(b-2c\right)\left(b^{2}+2bc+4c^{2}\right)
Rewrite b^{3}-8c^{3} as b^{3}-\left(2c\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
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