Solve b^2+2b+12=4c

$$b ^ { 2 } + 2 b + 12 = 4 c$$

Solve for c

$$c=\frac{b^{2}+2b+12}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4c=b^{2}+2b+12$$

Divide both sides by 4.

$$\frac{4c}{4}=\frac{b^{2}+2b+12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$c=\frac{b^{2}+2b+12}{4}$$

Divide b^{2}+2b+12 by 4.

$$c=\frac{b^{2}}{4}+\frac{b}{2}+3$$

Solve for b

$$b=\sqrt{4c-11}-1$$

$$b=-\sqrt{4c-11}-1\text{, }c\geq \frac{11}{4}$$