Solve b^2+1=0

$$b ^ { 2 } + 1 = 0$$

Solve for b

$$b=-i$$

$$b=i$$

Steps by Finding Square Root

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$b^{2}=-1$$

The equation is now solved.

$$b=i b=-i$$

Steps Using the Quadratic Formula

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$b^{2}+1=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$b=\frac{0±\sqrt{0^{2}-4}}{2}$$

Square 0.

$$b=\frac{0±\sqrt{-4}}{2}$$

Take the square root of -4.

$$b=\frac{0±2i}{2}$$

Now solve the equation b=\frac{0±2i}{2} when ± is plus.

$$b=i$$

Now solve the equation b=\frac{0±2i}{2} when ± is minus.

$$b=-i$$

The equation is now solved.

$$b=i b=-i$$