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b=\frac{6\sqrt{6}}{\left(\sqrt{6}\right)^{2}}-\frac{2\sqrt{6}}{\sqrt{6}}
Rationalize the denominator of \frac{6}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
b=\frac{6\sqrt{6}}{6}-\frac{2\sqrt{6}}{\sqrt{6}}
The square of \sqrt{6} is 6.
b=\sqrt{6}-\frac{2\sqrt{6}}{\sqrt{6}}
Cancel out 6 and 6.
b=\sqrt{6}-\frac{2\sqrt{6}\sqrt{6}}{\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{2\sqrt{6}}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
b=\sqrt{6}-\frac{2\sqrt{6}\sqrt{6}}{6}
The square of \sqrt{6} is 6.
b=\sqrt{6}-\frac{2\times 6}{6}
Multiply \sqrt{6} and \sqrt{6} to get 6.
b=\sqrt{6}-\frac{12}{6}
Multiply 2 and 6 to get 12.
b=\sqrt{6}-2
Divide 12 by 6 to get 2.