Solve b=1/3+1/4quadc2/5

$$b = \frac { 1 } { 3 } + \frac { 1 } { 4 } \quad c \frac { 2 } { 5 }$$

Solve for c

$$c=10b-\frac{10}{3}$$

Steps for Solving Linear Equation

Multiply \frac{1}{4} and \frac{2}{5} to get \frac{1}{10}.

$$b=\frac{1}{3}+\frac{1}{10}c$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}+\frac{1}{10}c=b$$

Subtract \frac{1}{3} from both sides.

$$\frac{1}{10}c=b-\frac{1}{3}$$

Multiply both sides by 10.

$$\frac{\frac{1}{10}c}{\frac{1}{10}}=\frac{b-\frac{1}{3}}{\frac{1}{10}}$$

Dividing by \frac{1}{10} undoes the multiplication by \frac{1}{10}.

$$c=\frac{b-\frac{1}{3}}{\frac{1}{10}}$$

Divide b-\frac{1}{3} by \frac{1}{10} by multiplying b-\frac{1}{3} by the reciprocal of \frac{1}{10}.

$$c=10b-\frac{10}{3}$$

Solve for b

$$b=\frac{c}{10}+\frac{1}{3}$$

Solution Steps

Multiply \frac{1}{4} and \frac{2}{5} to get \frac{1}{10}.

$$b=\frac{1}{3}+\frac{1}{10}c$$