Solve for a (complex solution)
\left\{\begin{matrix}a=-\frac{3b-2f}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=\frac{2f}{3}\text{ and }x=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=-\frac{3b-2f}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=\frac{2f}{3}\text{ and }x=0\end{matrix}\right.
Solve for b
b=\frac{2f-ax}{3}
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ax=2f-3b
Subtract 3b from both sides.
xa=2f-3b
The equation is in standard form.
\frac{xa}{x}=\frac{2f-3b}{x}
Divide both sides by x.
a=\frac{2f-3b}{x}
Dividing by x undoes the multiplication by x.
ax=2f-3b
Subtract 3b from both sides.
xa=2f-3b
The equation is in standard form.
\frac{xa}{x}=\frac{2f-3b}{x}
Divide both sides by x.
a=\frac{2f-3b}{x}
Dividing by x undoes the multiplication by x.
3b=2f-ax
Subtract ax from both sides.
\frac{3b}{3}=\frac{2f-ax}{3}
Divide both sides by 3.
b=\frac{2f-ax}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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