Factor
\left(z^{3}-2\right)\left(az+b\right)
Evaluate
\left(z^{3}-2\right)\left(az+b\right)
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z^{3}\left(az+b\right)-2\left(az+b\right)
Do the grouping az^{4}+bz^{3}-2az-2b=\left(az^{4}+bz^{3}\right)+\left(-2az-2b\right), and factor out z^{3} in the first and -2 in the second group.
\left(az+b\right)\left(z^{3}-2\right)
Factor out common term az+b by using distributive property. Polynomial z^{3}-2 is not factored since it does not have any rational roots.
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