Solve for a (complex solution)
\left\{\begin{matrix}a=\frac{cx+b+d}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=-d\text{ and }x=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=\frac{cx+b+d}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=-d\text{ and }x=0\end{matrix}\right.
Solve for b
b=ax-cx-d
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ax=cx+d+b
Add b to both sides.
xa=cx+b+d
The equation is in standard form.
\frac{xa}{x}=\frac{cx+b+d}{x}
Divide both sides by x.
a=\frac{cx+b+d}{x}
Dividing by x undoes the multiplication by x.
ax=cx+d+b
Add b to both sides.
xa=cx+b+d
The equation is in standard form.
\frac{xa}{x}=\frac{cx+b+d}{x}
Divide both sides by x.
a=\frac{cx+b+d}{x}
Dividing by x undoes the multiplication by x.
-b=cx+d-ax
Subtract ax from both sides.
-b=cx-ax+d
The equation is in standard form.
\frac{-b}{-1}=\frac{cx-ax+d}{-1}
Divide both sides by -1.
b=\frac{cx-ax+d}{-1}
Dividing by -1 undoes the multiplication by -1.
b=-\left(cx-ax+d\right)
Divide cx+d-ax by -1.
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