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Solve for a (complex solution)
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Solve for a
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ax-7b-3ax=-c
Subtract 3ax from both sides.
-2ax-7b=-c
Combine ax and -3ax to get -2ax.
-2ax=-c+7b
Add 7b to both sides.
\left(-2x\right)a=7b-c
The equation is in standard form.
\frac{\left(-2x\right)a}{-2x}=\frac{7b-c}{-2x}
Divide both sides by -2x.
a=\frac{7b-c}{-2x}
Dividing by -2x undoes the multiplication by -2x.
a=-\frac{7b-c}{2x}
Divide -c+7b by -2x.
ax-7b-3ax=-c
Subtract 3ax from both sides.
-2ax-7b=-c
Combine ax and -3ax to get -2ax.
-2ax=-c+7b
Add 7b to both sides.
\left(-2x\right)a=7b-c
The equation is in standard form.
\frac{\left(-2x\right)a}{-2x}=\frac{7b-c}{-2x}
Divide both sides by -2x.
a=\frac{7b-c}{-2x}
Dividing by -2x undoes the multiplication by -2x.
a=-\frac{7b-c}{2x}
Divide -c+7b by -2x.
-7b=3ax-c-ax
Subtract ax from both sides.
-7b=2ax-c
Combine 3ax and -ax to get 2ax.
\frac{-7b}{-7}=\frac{2ax-c}{-7}
Divide both sides by -7.
b=\frac{2ax-c}{-7}
Dividing by -7 undoes the multiplication by -7.
b=\frac{c-2ax}{7}
Divide 2ax-c by -7.