Solve ax-1=bx+2

$$a x - 1 = b x + 2$$

Solve for a

$$a=b+\frac{3}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Add 1 to both sides.

$$ax=bx+2+1$$

Add 2 and 1 to get 3.

$$ax=bx+3$$

The equation is in standard form.

$$xa=bx+3$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{bx+3}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{bx+3}{x}$$

Divide bx+3 by x.

$$a=b+\frac{3}{x}$$

Solve for b

$$b=a-\frac{3}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx+2=ax-1$$

Subtract 2 from both sides.

$$bx=ax-1-2$$

Subtract 2 from -1 to get -3.

$$bx=ax-3$$

The equation is in standard form.

$$xb=ax-3$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{ax-3}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{ax-3}{x}$$

Divide ax-3 by x.

$$b=a-\frac{3}{x}$$