Solve ax^71+bx^51+6=10

$$a x ^ { 71 } + b x ^ { 51 } + 6 = 10$$

Solve for a

$$a=\frac{4-bx^{51}}{x^{71}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract bx^{51} from both sides.

$$ax^{71}+6=10-bx^{51}$$

Subtract 6 from both sides.

$$ax^{71}=10-bx^{51}-6$$

Subtract 6 from 10 to get 4.

$$ax^{71}=4-bx^{51}$$

The equation is in standard form.

$$x^{71}a=4-bx^{51}$$

Divide both sides by x^{71}.

$$\frac{x^{71}a}{x^{71}}=\frac{4-bx^{51}}{x^{71}}$$

Dividing by x^{71} undoes the multiplication by x^{71}.

$$a=\frac{4-bx^{51}}{x^{71}}$$

Divide 4-bx^{51} by x^{71}.

$$a=-\frac{b}{x^{20}}+\frac{4}{x^{71}}$$

Solve for b

$$b=\frac{4-ax^{71}}{x^{51}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract ax^{71} from both sides.

$$bx^{51}+6=10-ax^{71}$$

Subtract 6 from both sides.

$$bx^{51}=10-ax^{71}-6$$

Subtract 6 from 10 to get 4.

$$bx^{51}=4-ax^{71}$$

The equation is in standard form.

$$x^{51}b=4-ax^{71}$$

Divide both sides by x^{51}.

$$\frac{x^{51}b}{x^{51}}=\frac{4-ax^{71}}{x^{51}}$$

Dividing by x^{51} undoes the multiplication by x^{51}.

$$b=\frac{4-ax^{71}}{x^{51}}$$

Divide 4-ax^{71} by x^{51}.

$$b=-ax^{20}+\frac{4}{x^{51}}$$