Solve for a
\left\{\begin{matrix}a=-\frac{b^{3}-15}{x^{3}}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=\sqrt[3]{15}\text{ and }x=0\end{matrix}\right.
Solve for b
b=\sqrt[3]{15-ax^{3}}
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ax^{3}=15-b^{3}
Subtract b^{3} from both sides.
x^{3}a=15-b^{3}
The equation is in standard form.
\frac{x^{3}a}{x^{3}}=\frac{15-b^{3}}{x^{3}}
Divide both sides by x^{3}.
a=\frac{15-b^{3}}{x^{3}}
Dividing by x^{3} undoes the multiplication by x^{3}.
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