Solve ax^2+7=16

$$a x ^ { 2 } + 7 = 16$$

Solve for a

$$a=\frac{9}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 7 from both sides.

$$ax^{2}=16-7$$

Subtract 7 from 16 to get 9.

$$ax^{2}=9$$

The equation is in standard form.

$$x^{2}a=9$$

Divide both sides by x^{2}.

$$\frac{x^{2}a}{x^{2}}=\frac{9}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$a=\frac{9}{x^{2}}$$

Solve for x (complex solution)

$$x=-3a^{-\frac{1}{2}}$$

$$x=3a^{-\frac{1}{2}}\text{, }a\neq 0$$

Solve for x

$$x=\frac{3}{\sqrt{a}}$$

$$x=-\frac{3}{\sqrt{a}}\text{, }a>0$$