Solve ax^2+b/x=0

$$a x ^ { 2 } + \frac { b } { x } = 0$$

Solve for a

$$a=-\frac{b}{x^{3}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$ax^{2}x+b=0$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$ax^{3}+b=0$$

Subtract b from both sides. Anything subtracted from zero gives its negation.

$$ax^{3}=-b$$

The equation is in standard form.

$$x^{3}a=-b$$

Divide both sides by x^{3}.

$$\frac{x^{3}a}{x^{3}}=-\frac{b}{x^{3}}$$

Dividing by x^{3} undoes the multiplication by x^{3}.

$$a=-\frac{b}{x^{3}}$$

Solve for b

$$b=-ax^{3}$$

$$x\neq 0$$

Solution Steps

Multiply both sides of the equation by x.

$$ax^{2}x+b=0$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$ax^{3}+b=0$$

Subtract ax^{3} from both sides. Anything subtracted from zero gives its negation.

$$b=-ax^{3}$$