Solve for a (complex solution)
\left\{\begin{matrix}a=\frac{7x+b-8}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&x=0\text{ and }b=8\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=\frac{7x+b-8}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }b=8\end{matrix}\right.
Solve for b
b=ax-7x+8
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ax=7x+b-8
Subtract 8 from both sides.
xa=7x+b-8
The equation is in standard form.
\frac{xa}{x}=\frac{7x+b-8}{x}
Divide both sides by x.
a=\frac{7x+b-8}{x}
Dividing by x undoes the multiplication by x.
ax=7x+b-8
Subtract 8 from both sides.
xa=7x+b-8
The equation is in standard form.
\frac{xa}{x}=\frac{7x+b-8}{x}
Divide both sides by x.
a=\frac{7x+b-8}{x}
Dividing by x undoes the multiplication by x.
7x+b=ax+8
Swap sides so that all variable terms are on the left hand side.
b=ax+8-7x
Subtract 7x from both sides.
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