Solve ax+3x=bx+5

$$a x + 3 x = b x + 5$$

Solve for a

$$a=b-3+\frac{5}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 3x from both sides.

$$ax=bx+5-3x$$

The equation is in standard form.

$$xa=bx-3x+5$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{bx-3x+5}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{bx-3x+5}{x}$$

Divide bx+5-3x by x.

$$a=b-3+\frac{5}{x}$$

Solve for b

$$b=a+3-\frac{5}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx+5=ax+3x$$

Subtract 5 from both sides.

$$bx=ax+3x-5$$

The equation is in standard form.

$$xb=ax+3x-5$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{ax+3x-5}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{ax+3x-5}{x}$$

Divide ax+3x-5 by x.

$$b=a+3-\frac{5}{x}$$