Solve for a (complex solution)
\left\{\begin{matrix}a=-\frac{12+b-x}{4x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&x=0\text{ and }b=-12\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=-\frac{12+b-x}{4x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }b=-12\end{matrix}\right.
Solve for b
b=-4ax+x-12
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4ax+12=x-b
Multiply both sides of the equation by 4.
4ax=x-b-12
Subtract 12 from both sides.
4xa=x-b-12
The equation is in standard form.
\frac{4xa}{4x}=\frac{x-b-12}{4x}
Divide both sides by 4x.
a=\frac{x-b-12}{4x}
Dividing by 4x undoes the multiplication by 4x.
4ax+12=x-b
Multiply both sides of the equation by 4.
4ax=x-b-12
Subtract 12 from both sides.
4xa=x-b-12
The equation is in standard form.
\frac{4xa}{4x}=\frac{x-b-12}{4x}
Divide both sides by 4x.
a=\frac{x-b-12}{4x}
Dividing by 4x undoes the multiplication by 4x.
4ax+12=x-b
Multiply both sides of the equation by 4.
x-b=4ax+12
Swap sides so that all variable terms are on the left hand side.
-b=4ax+12-x
Subtract x from both sides.
-b=4ax-x+12
The equation is in standard form.
\frac{-b}{-1}=\frac{4ax-x+12}{-1}
Divide both sides by -1.
b=\frac{4ax-x+12}{-1}
Dividing by -1 undoes the multiplication by -1.
b=-4ax+x-12
Divide -x+4ax+12 by -1.
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