Solve for a
\left\{\begin{matrix}a=-\frac{-2cx+2d-5b}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&d=\frac{5b}{2}\text{ and }x=0\end{matrix}\right.
Solve for b
b=\frac{ax-2cx+2d}{5}
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ax=2cx+5b-2d
Subtract 2d from both sides.
xa=2cx+5b-2d
The equation is in standard form.
\frac{xa}{x}=\frac{2cx+5b-2d}{x}
Divide both sides by x.
a=\frac{2cx+5b-2d}{x}
Dividing by x undoes the multiplication by x.
2cx+5b=ax+2d
Swap sides so that all variable terms are on the left hand side.
5b=ax+2d-2cx
Subtract 2cx from both sides.
5b=ax-2cx+2d
The equation is in standard form.
\frac{5b}{5}=\frac{ax-2cx+2d}{5}
Divide both sides by 5.
b=\frac{ax-2cx+2d}{5}
Dividing by 5 undoes the multiplication by 5.
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