Solve an=a_{1}+(n-3)-n

$$a n = a _ { 1 } + ( n - 3 ) - n$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{a_{1}-3}{n}\text{, }&n\neq 0\\a\in \mathrm{C}\text{, }&a_{1}=3\text{ and }n=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine n and -n to get 0.

$$an=a_{1}-3$$

The equation is in standard form.

$$na=a_{1}-3$$

Divide both sides by n.

$$\frac{na}{n}=\frac{a_{1}-3}{n}$$

Dividing by n undoes the multiplication by n.

$$a=\frac{a_{1}-3}{n}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{a_{1}-3}{n}\text{, }&n\neq 0\\a\in \mathrm{R}\text{, }&a_{1}=3\text{ and }n=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine n and -n to get 0.

$$an=a_{1}-3$$

The equation is in standard form.

$$na=a_{1}-3$$

Divide both sides by n.

$$\frac{na}{n}=\frac{a_{1}-3}{n}$$

Dividing by n undoes the multiplication by n.

$$a=\frac{a_{1}-3}{n}$$

Solve for a_1

$$a_{1}=an+3$$

Solution Steps

Combine n and -n to get 0.

$$an=a_{1}-3$$

Swap sides so that all variable terms are on the left hand side.

$$a_{1}-3=an$$

Add 3 to both sides.

$$a_{1}=an+3$$