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an\left(n^{2}+1\right)=n-1
Multiply both sides of the equation by n^{2}+1.
an^{3}+an=n-1
Use the distributive property to multiply an by n^{2}+1.
\left(n^{3}+n\right)a=n-1
Combine all terms containing a.
\frac{\left(n^{3}+n\right)a}{n^{3}+n}=\frac{n-1}{n^{3}+n}
Divide both sides by n^{3}+n.
a=\frac{n-1}{n^{3}+n}
Dividing by n^{3}+n undoes the multiplication by n^{3}+n.
a=\frac{n-1}{n\left(n^{2}+1\right)}
Divide n-1 by n^{3}+n.