Solve abc=2*ab+120

$$a b c = 2 \cdot a b + 120$$

Solve for a

$$a=\frac{120}{b\left(c-2\right)}$$

$$c\neq 2\text{ and }b\neq 0$$

Steps for Solving Linear Equation

Subtract 2ab from both sides.

$$abc-2ab=120$$

Combine all terms containing a.

$$\left(bc-2b\right)a=120$$

Divide both sides by bc-2b.

$$\frac{\left(bc-2b\right)a}{bc-2b}=\frac{120}{bc-2b}$$

Dividing by bc-2b undoes the multiplication by bc-2b.

$$a=\frac{120}{bc-2b}$$

Divide 120 by bc-2b.

$$a=\frac{120}{b\left(c-2\right)}$$

Solve for b

$$b=\frac{120}{a\left(c-2\right)}$$

$$c\neq 2\text{ and }a\neq 0$$

Steps for Solving Linear Equation

Subtract 2ab from both sides.

$$abc-2ab=120$$

Combine all terms containing b.

$$\left(ac-2a\right)b=120$$

Divide both sides by ac-2a.

$$\frac{\left(ac-2a\right)b}{ac-2a}=\frac{120}{ac-2a}$$

Dividing by ac-2a undoes the multiplication by ac-2a.

$$b=\frac{120}{ac-2a}$$

Divide 120 by ac-2a.

$$b=\frac{120}{a\left(c-2\right)}$$