Solve for a
a=\frac{1}{b+3}
b\neq -3
Solve for b
b=-3+\frac{1}{a}
a\neq 0
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ab+3a=1
Add 3a to both sides.
\left(b+3\right)a=1
Combine all terms containing a.
\frac{\left(b+3\right)a}{b+3}=\frac{1}{b+3}
Divide both sides by b+3.
a=\frac{1}{b+3}
Dividing by b+3 undoes the multiplication by b+3.
ab=1-3a
The equation is in standard form.
\frac{ab}{a}=\frac{1-3a}{a}
Divide both sides by a.
b=\frac{1-3a}{a}
Dividing by a undoes the multiplication by a.
b=-3+\frac{1}{a}
Divide -3a+1 by a.
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