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a\left(b+c\right)+10\left(b+c\right)
Do the grouping ab+ac+10b+10c=\left(ab+ac\right)+\left(10b+10c\right), and factor out a in the first and 10 in the second group.
\left(b+c\right)\left(a+10\right)
Factor out common term b+c by using distributive property.