Solve ab+4a+4b-9=96

$$a b + 4 a + 4 b - 9 = 96$$

Solve for a

$$a=-\frac{4b-105}{b+4}$$

$$b\neq -4$$

Steps for Solving Linear Equation

Subtract 4b from both sides.

$$ab+4a-9=96-4b$$

Add 9 to both sides.

$$ab+4a=96-4b+9$$

Add 96 and 9 to get 105.

$$ab+4a=105-4b$$

Combine all terms containing a.

$$\left(b+4\right)a=105-4b$$

Divide both sides by b+4.

$$\frac{\left(b+4\right)a}{b+4}=\frac{105-4b}{b+4}$$

Dividing by b+4 undoes the multiplication by b+4.

$$a=\frac{105-4b}{b+4}$$

Solve for b

$$b=-\frac{4a-105}{a+4}$$

$$a\neq -4$$

Steps for Solving Linear Equation

Subtract 4a from both sides.

$$ab+4b-9=96-4a$$

Add 9 to both sides.

$$ab+4b=96-4a+9$$

Add 96 and 9 to get 105.

$$ab+4b=105-4a$$

Combine all terms containing b.

$$\left(a+4\right)b=105-4a$$

Divide both sides by a+4.

$$\frac{\left(a+4\right)b}{a+4}=\frac{105-4a}{a+4}$$

Dividing by a+4 undoes the multiplication by a+4.

$$b=\frac{105-4a}{a+4}$$