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Solve for N
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Solve for S_40
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5N+6S_{40}=a_{n}
Swap sides so that all variable terms are on the left hand side.
5N=a_{n}-6S_{40}
Subtract 6S_{40} from both sides.
\frac{5N}{5}=\frac{a_{n}-6S_{40}}{5}
Divide both sides by 5.
N=\frac{a_{n}-6S_{40}}{5}
Dividing by 5 undoes the multiplication by 5.
5N+6S_{40}=a_{n}
Swap sides so that all variable terms are on the left hand side.
6S_{40}=a_{n}-5N
Subtract 5N from both sides.
\frac{6S_{40}}{6}=\frac{a_{n}-5N}{6}
Divide both sides by 6.
S_{40}=\frac{a_{n}-5N}{6}
Dividing by 6 undoes the multiplication by 6.