Solve for n
n=-\frac{2a_{n}-1}{a_{n}-2}
a_{n}\neq 2
Solve for a_n
a_{n}=\frac{2n+1}{n+2}
n\neq -2
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a_{n}\left(n+2\right)=2n+1
Variable n cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by n+2.
a_{n}n+2a_{n}=2n+1
Use the distributive property to multiply a_{n} by n+2.
a_{n}n+2a_{n}-2n=1
Subtract 2n from both sides.
a_{n}n-2n=1-2a_{n}
Subtract 2a_{n} from both sides.
\left(a_{n}-2\right)n=1-2a_{n}
Combine all terms containing n.
\frac{\left(a_{n}-2\right)n}{a_{n}-2}=\frac{1-2a_{n}}{a_{n}-2}
Divide both sides by a_{n}-2.
n=\frac{1-2a_{n}}{a_{n}-2}
Dividing by a_{n}-2 undoes the multiplication by a_{n}-2.
n=\frac{1-2a_{n}}{a_{n}-2}\text{, }n\neq -2
Variable n cannot be equal to -2.
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