Solve a_0^0=45-5p_{0}+5+2*10

$$a _ { 0 } ^ { 0 } = 45 - 5 p _ { 0 } + 5 + 2 \times 10$$

Solve for p_0

$$p_{0} = \frac{69}{5} = 13\frac{4}{5} = 13.8$$

$$a_{0}\neq 0$$

Steps for Solving Linear Equation

Add 45 and 5 to get 50.

$$a_{0}^{0}=50-5p_{0}+2\times 10$$

Multiply 2 and 10 to get 20.

$$a_{0}^{0}=50-5p_{0}+20$$

Add 50 and 20 to get 70.

$$a_{0}^{0}=70-5p_{0}$$

Swap sides so that all variable terms are on the left hand side.

$$70-5p_{0}=a_{0}^{0}$$

Subtract 70 from both sides.

$$-5p_{0}=a_{0}^{0}-70$$

The equation is in standard form.

$$-5p_{0}=-69$$

Divide both sides by -5.

$$\frac{-5p_{0}}{-5}=-\frac{69}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$p_{0}=-\frac{69}{-5}$$

Divide -69 by -5.

$$p_{0}=\frac{69}{5}$$

Solve for a_0

$$a_{0}\neq 0$$

$$p_{0}=\frac{69}{5}\text{ and }a_{0}\neq 0$$