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Solve for a_3
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Solve for b
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ba_{3}=9b
The equation is in standard form.
\frac{ba_{3}}{b}=\frac{9b}{b}
Divide both sides by b.
a_{3}=\frac{9b}{b}
Dividing by b undoes the multiplication by b.
a_{3}=9
Divide 9b by b.
a_{3}b-9b=0
Subtract 9b from both sides.
\left(a_{3}-9\right)b=0
Combine all terms containing b.
b=0
Divide 0 by -9+a_{3}.