Solve a2^2x-1=32

$$a 2 ^ { 2 x - 1 } = 32$$

Solve for a

$$a=\frac{64}{2^{2x}}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$2^{2x-1}a=32$$

Divide both sides by 2^{2x-1}.

$$\frac{2^{2x-1}a}{2^{2x-1}}=\frac{32}{2^{2x-1}}$$

Dividing by 2^{2x-1} undoes the multiplication by 2^{2x-1}.

$$a=\frac{32}{2^{2x-1}}$$

Divide 32 by 2^{2x-1}.

$$a=2^{6-2x}$$

Solve for x (complex solution)

$$x=-\frac{\log_{2}\left(a\right)}{2}+\frac{\pi n_{1}i}{\ln(2)}+3$$

$$n_{1}\in \mathrm{Z}$$

$$a\neq 0$$

Solve for x

$$x=-\frac{\log_{2}\left(a\right)}{2}+3$$

$$a>0$$