Solve for B (complex solution)
\left\{\begin{matrix}B=\frac{a-C}{x}\text{, }&x\neq 0\\B\in \mathrm{C}\text{, }&a=C\text{ and }x=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=\frac{a-C}{x}\text{, }&x\neq 0\\B\in \mathrm{R}\text{, }&a=C\text{ and }x=0\end{matrix}\right.
Solve for C
C=a-Bx
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-Bx=C-a
Subtract a from both sides.
\left(-x\right)B=C-a
The equation is in standard form.
\frac{\left(-x\right)B}{-x}=\frac{C-a}{-x}
Divide both sides by -x.
B=\frac{C-a}{-x}
Dividing by -x undoes the multiplication by -x.
B=-\frac{C-a}{x}
Divide -a+C by -x.
-Bx=C-a
Subtract a from both sides.
\left(-x\right)B=C-a
The equation is in standard form.
\frac{\left(-x\right)B}{-x}=\frac{C-a}{-x}
Divide both sides by -x.
B=\frac{C-a}{-x}
Dividing by -x undoes the multiplication by -x.
B=-\frac{C-a}{x}
Divide C-a by -x.
C=a-Bx
Swap sides so that all variable terms are on the left hand side.
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