Solve a(9)^2+b(9)+c=-2

$$a ( 9 ) ^ { 2 } + b ( 9 ) + c = - 2$$

Solve for a

$$a=-\frac{b}{9}-\frac{c}{81}-\frac{2}{81}$$

Steps for Solving Linear Equation

Calculate 9 to the power of 2 and get 81.

$$a\times 81+b\times 9+c=-2$$

Subtract b\times 9 from both sides.

$$a\times 81+c=-2-b\times 9$$

Subtract c from both sides.

$$a\times 81=-2-b\times 9-c$$

Multiply -1 and 9 to get -9.

$$a\times 81=-2-9b-c$$

The equation is in standard form.

$$81a=-9b-c-2$$

Divide both sides by 81.

$$\frac{81a}{81}=\frac{-9b-c-2}{81}$$

Dividing by 81 undoes the multiplication by 81.

$$a=\frac{-9b-c-2}{81}$$

Divide -2-9b-c by 81.

$$a=-\frac{b}{9}-\frac{c}{81}-\frac{2}{81}$$

Solve for b

$$b=-\frac{c}{9}-9a-\frac{2}{9}$$

Steps for Solving Linear Equation

Calculate 9 to the power of 2 and get 81.

$$a\times 81+b\times 9+c=-2$$

Subtract a\times 81 from both sides.

$$b\times 9+c=-2-a\times 81$$

Subtract c from both sides.

$$b\times 9=-2-a\times 81-c$$

Multiply -1 and 81 to get -81.

$$b\times 9=-2-81a-c$$

The equation is in standard form.

$$9b=-81a-c-2$$

Divide both sides by 9.

$$\frac{9b}{9}=\frac{-81a-c-2}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$b=\frac{-81a-c-2}{9}$$

Divide -2-81a-c by 9.

$$b=-\frac{c}{9}-9a-\frac{2}{9}$$