Solve a(2)^c+3=1

$$a ( 2 ) ^ { c } + 3 = 1$$

Solve for a

$$a=-2^{1-c}$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$a\times 2^{c}=1-3$$

Subtract 3 from 1 to get -2.

$$a\times 2^{c}=-2$$

The equation is in standard form.

$$2^{c}a=-2$$

Divide both sides by 2^{c}.

$$\frac{2^{c}a}{2^{c}}=-\frac{2}{2^{c}}$$

Dividing by 2^{c} undoes the multiplication by 2^{c}.

$$a=-\frac{2}{2^{c}}$$

Solve for c

$$c=\log_{2}\left(-\frac{2}{a}\right)$$

$$a<0$$