Solve a(2)+b(3)=2

$$a ( 2 ) + b ( 3 ) = 2$$

Solve for a

$$a=-\frac{3b}{2}+1$$

Steps for Solving Linear Equation

Subtract b\times 3 from both sides.

$$a\times 2=2-b\times 3$$

Multiply -1 and 3 to get -3.

$$a\times 2=2-3b$$

The equation is in standard form.

$$2a=2-3b$$

Divide both sides by 2.

$$\frac{2a}{2}=\frac{2-3b}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$a=\frac{2-3b}{2}$$

Divide 2-3b by 2.

$$a=-\frac{3b}{2}+1$$

Solve for b

$$b=\frac{2-2a}{3}$$

Steps for Solving Linear Equation

Subtract a\times 2 from both sides.

$$b\times 3=2-a\times 2$$

Multiply -1 and 2 to get -2.

$$b\times 3=2-2a$$

The equation is in standard form.

$$3b=2-2a$$

Divide both sides by 3.

$$\frac{3b}{3}=\frac{2-2a}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$b=\frac{2-2a}{3}$$