Solve a(-63)+beta(3-9)=c-2

$$a ( - 63 ) + \beta ( 3 - 9 ) = c - 2$$

Solve for a

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Steps for Solving Linear Equation

Subtract 9 from 3 to get -6.

$$a\left(-63\right)+\beta \left(-6\right)=c-2$$

Subtract \beta \left(-6\right) from both sides.

$$a\left(-63\right)=c-2-\beta \left(-6\right)$$

Multiply -1 and -6 to get 6.

$$a\left(-63\right)=c-2+6\beta$$

The equation is in standard form.

$$-63a=c+6\beta -2$$

Divide both sides by -63.

$$\frac{-63a}{-63}=\frac{c+6\beta -2}{-63}$$

Dividing by -63 undoes the multiplication by -63.

$$a=\frac{c+6\beta -2}{-63}$$

Divide c-2+6\beta by -63.

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Solve for c

$$c=2-6\beta -63a$$