Solve a(-6.3)+beta(3.-9)=c-2

$$a ( - 6.3 ) + \beta ( 3 . - 9 ) = c - 2$$

Solve for a

$$a=-\frac{10c}{63}-\frac{20\beta }{21}+\frac{20}{63}$$

Steps for Solving Linear Equation

Subtract 9 from 3 to get -6.

$$a\left(-6.3\right)+\beta \left(-6\right)=c-2$$

Subtract \beta \left(-6\right) from both sides.

$$a\left(-6.3\right)=c-2-\beta \left(-6\right)$$

Multiply -1 and -6 to get 6.

$$a\left(-6.3\right)=c-2+6\beta$$

The equation is in standard form.

$$-6.3a=c+6\beta -2$$

Divide both sides of the equation by -6.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-6.3a}{-6.3}=\frac{c+6\beta -2}{-6.3}$$

Dividing by -6.3 undoes the multiplication by -6.3.

$$a=\frac{c+6\beta -2}{-6.3}$$

Divide c-2+6\beta by -6.3 by multiplying c-2+6\beta by the reciprocal of -6.3.

$$a=-\frac{10c}{63}-\frac{20\beta }{21}+\frac{20}{63}$$

Solve for c

$$c=-\frac{63a}{10}-6\beta +2$$