Solve a*10+b*3+c*0.5=100

$$a \times 10 + b \times 3 + c \times 0.5 = 100$$

Solve for a

$$a=-\frac{c}{20}-\frac{3b}{10}+10$$

Steps for Solving Linear Equation

Subtract b\times 3 from both sides.

$$a\times 10+c\times 0.5=100-b\times 3$$

Subtract c\times 0.5 from both sides.

$$a\times 10=100-b\times 3-c\times 0.5$$

Multiply -1 and 3 to get -3.

$$a\times 10=100-3b-c\times 0.5$$

Multiply -1 and 0.5 to get -0.5.

$$a\times 10=100-3b-0.5c$$

The equation is in standard form.

$$10a=-\frac{c}{2}-3b+100$$

Divide both sides by 10.

$$\frac{10a}{10}=\frac{-\frac{c}{2}-3b+100}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$a=\frac{-\frac{c}{2}-3b+100}{10}$$

Divide 100-3b-\frac{c}{2} by 10.

$$a=-\frac{c}{20}-\frac{3b}{10}+10$$

Solve for b

$$b=-\frac{c}{6}-\frac{10a}{3}+\frac{100}{3}$$

Steps for Solving Linear Equation

Subtract a\times 10 from both sides.

$$b\times 3+c\times 0.5=100-a\times 10$$

Subtract c\times 0.5 from both sides.

$$b\times 3=100-a\times 10-c\times 0.5$$

Multiply -1 and 10 to get -10.

$$b\times 3=100-10a-c\times 0.5$$

Multiply -1 and 0.5 to get -0.5.

$$b\times 3=100-10a-0.5c$$

The equation is in standard form.

$$3b=-\frac{c}{2}-10a+100$$

Divide both sides by 3.

$$\frac{3b}{3}=\frac{-\frac{c}{2}-10a+100}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$b=\frac{-\frac{c}{2}-10a+100}{3}$$

Divide 100-10a-\frac{c}{2} by 3.

$$b=-\frac{c}{6}-\frac{10a}{3}+\frac{100}{3}$$