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\left(a^{2}+b^{2}\right)\left(a^{4}-a^{2}b^{2}+b^{4}\right)
Rewrite a^{6}+b^{6} as \left(a^{2}\right)^{3}+\left(b^{2}\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).