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t^{2}-110t+900=0
Substitute t for a^{2}.
t=\frac{-\left(-110\right)±\sqrt{\left(-110\right)^{2}-4\times 1\times 900}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -110 for b, and 900 for c in the quadratic formula.
t=\frac{110±10\sqrt{85}}{2}
Do the calculations.
t=5\sqrt{85}+55 t=55-5\sqrt{85}
Solve the equation t=\frac{110±10\sqrt{85}}{2} when ± is plus and when ± is minus.
a=\frac{\sqrt{170}+5\sqrt{2}}{2} a=-\frac{\sqrt{170}+5\sqrt{2}}{2} a=-\frac{5\sqrt{2}-\sqrt{170}}{2} a=\frac{5\sqrt{2}-\sqrt{170}}{2}
Since a=t^{2}, the solutions are obtained by evaluating a=±\sqrt{t} for each t.