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\left(ab^{2}-2\right)\left(a^{2}b^{4}+2ab^{2}+4\right)
Rewrite a^{3}b^{6}-8 as \left(ab^{2}\right)^{3}-2^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).