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\left(x^{2}+ab\right)\left(x^{4}-abx^{2}+a^{2}b^{2}\right)
Rewrite a^{3}b^{3}+x^{6} as \left(x^{2}\right)^{3}+\left(ab\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).