Factor
\left(a-4\right)\left(a^{2}+4a+16\right)
Evaluate
a^{3}-64
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\left(a-4\right)\left(a^{2}+4a+16\right)
Rewrite a^{3}-64 as a^{3}-4^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right). Polynomial a^{2}+4a+16 is not factored since it does not have any rational roots.
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