Factor
\left(a+4\right)\left(a^{2}-4a+16\right)
Evaluate
a^{3}+64
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\left(a+4\right)\left(a^{2}-4a+16\right)
Rewrite a^{3}+64 as a^{3}+4^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right). Polynomial a^{2}-4a+16 is not factored since it does not have any rational roots.
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